-16t^2+34.14+43.89=0

Solution for -16t^2+34.14+43.89=0 equation:

-16t^2+34.14+43.89=0

We add all the numbers together, and all the variables

-16t^2+78.03=0

a = -16; b = 0; c = +78.03;
Δ = b2-4ac
Δ = 02-4·(-16)·78.03
Δ = 4993.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{4993.92}}{2*-16}=\frac{0-\sqrt{4993.92}}{-32}
=-\frac{\sqrt{}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{4993.92}}{2*-16}=\frac{0+\sqrt{4993.92}}{-32}
=\frac{\sqrt{}}{-32}
$